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• # 113304
• Wed 29 Jun 2016 02:25 PM

I have 7781 passengers , some spent 14 nights and some spent 7 nights - how to calculate how many passengers spent 7 nights and how many spent 14 nights.

Thanks

Arlette

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• # 113322
• Fri 01 Jul 2016 04:35 PM

I think that on first glance, since 7781 is not exactly divisable by 7, and 14 is a multiple of 7, then this is not able to be calculated.  

However, if the number was say 7784 then dividing by 7 gives 1112 and dividing by 14 gives 556.  so 556 14 nighters would leave nil available 7 nighters.

now if there were 555 14 nighters that would leave 2 7 nighters. and so on: 

etc until you get 0 14 nighters and 1112 7 nighters.

How you decide which combination is correct,,,, well, i don't think you can determine that.

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• # 113327
• Sat 02 Jul 2016 10:04 AM

But the 7781 isn't the number of nights but the number of passengers.  I think Arlette needs to provide more info.   

• Time can never be replaced. Spend it wisely.

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• # 113328
• Sat 02 Jul 2016 01:28 PM

Arlette the problem is unsolvable, you have 2 unknowns and 1 equation.

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• # 113330
• Sat 02 Jul 2016 06:02 PM

Hi Arlette,

I agree with davidst. The question doesnt make sense its too openended, any answer could be correct. 7780 couod have spent 14 nights and 1 couldve spend 7 and visa versa. Is there more to the question?

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